void* memcpy(void* destination, const void* source, size_t num);
#include#include int main() { int arr1[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }; int arr2[20] = { 0 }; //将arr1中的内容,拷贝到arr2中 memcpy(arr2, arr1, 40); // int* int* int i = 0; for (i = 0; i < 20; i++) { printf("%d ", arr2[i]);//1 2 3 4 5 6 7 8 9 10 0 0 0 0 0 0 0 0 0 0 } return 0; }
#include#include int main() { float arr1[] = { 1.0, 2.0, 3.0 }; float arr2[5] = { 0 }; //将arr1中的内容,拷贝到arr2中 memcpy(arr2, arr1, 8); // float* float* int i = 0; for (i = 0; i < 5; i++) { printf("%f ", arr2[i]);//1.000000 2.000000 0.000000 0.000000 0.000000 } return 0; }
memcpy的模拟实现:
#include#include //函数拷贝结束后,返回目标空间的起始地址 void* my_memcpy(void* dest, const void* src, size_t num) { void* ret = dest; assert(dest && src); while (num--) { *(char*)dest = *(char*)src; dest = (char*)dest + 1; src = (char*)src + 1; //强制类型转换是临时的,不是永久的 } return ret; } int main() { int arr1[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }; int arr2[20] = { 0 }; my_memcpy(arr2, arr1, 20); int i = 0; for (i = 0; i < 20; i++) { printf("%d ", arr2[i]);//1 2 3 4 5 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 } return 0; }
如果目标空间和源头空间有重合,就会出现以下情况:
#include#include //函数拷贝结束后,返回目标空间的起始地址 void* my_memcpy(void* dest, const void* src, size_t num) { void* ret = dest; assert(dest && src); while (num--) { *(char*)dest = *(char*)src; dest = (char*)dest + 1; src = (char*)src + 1; //强制类型转换是临时的,不是永久的 } return ret; } int main() { int arr1[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }; my_memcpy(arr1 + 2, arr1, 20); int i = 0; for (i = 0; i < 10; i++) { printf("%d ", arr1[i]);//1 2 1 2 1 2 1 8 9 10 } return 0; }
因此,不重叠是用来处理
void* memmove(void* destination, const void* source, size_t num);
#include#include int main() { int arr1[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }; memmove(arr1 + 2, arr1, 20); int i = 0; for (i = 0; i < 10; i++) { printf("%d ", arr1[i]);//1 2 1 2 3 4 5 8 9 10 } return 0; }
memmove的模拟实现:
#include字节#include void* my_memmove(void* dest, const void* src, size_t num) { void* ret = dest; assert(dest && src); if (dest < src) { //前->后 while (num--) { *(char*)dest = *(char*)src; dest = (char*)dest + 1; src = (char*)src + 1; } } else { //后->前 while (num--) { *((char*)dest + num) = *((char*)src + num); } } return ret; } int main() { int arr1[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }; my_memmove(arr1 + 2, arr1, 20);//1 2 1 2 3 4 5 8 9 10 //my_memmove(arr1, arr1 + 2, 20);//3 4 5 6 7 6 7 8 9 10 int i = 0; for (i = 0; i < 10; i++) { printf("%d ", arr1[i]); } return 0; }
int memcmp(const void* ptr1, const void* ptr2, size_t num);
#include#include int main() { int arr1[] = { 1, 2, 1, 4, 5, 6 }; int arr2[] = { 1, 2, 257 }; //int ret = memcmp(arr1, arr2, 9); //printf("%d\n", ret);//0 int ret = memcmp(arr1, arr2, 10); printf("%d\n", ret);//-1 return 0; }
void* memset(void* ptr, int value, size_t num);
#include#include int main() { char arr[] = "hello bit"; memset(arr + 1, 'x', 4);//以字节为单位设置的 printf("%s\n", arr);//hxxxx bit return 0; }
#includeint main() { int arr[10] = { 0 }; memset(arr, 1, 10); return 0; }